Since 4i is a root, that automatically means -4i is also a root (complex roots always travel in pairs)
So the factored form would look like
<span>(x+4i)(x−4i).</span>
When multiplied out this gives the polynomial
<span><span>x2</span>+<span>16.</span></span>
Any line can be expressed in the form y=mx+b where m is the slope and b is y intercept.
Two lines can either be parallel ,overlap or meet at one point .Let us look at different cases :
1)When two lines are parallel they do not intersect at any point and hence the system of equations have no solution.
2) When two lines overlap each other then the two lines touch each other at infinite number of points and we say the system of equations have infinite solutions.
3) When two lines intersect each other at one point we say the system of equation has one solution.
Part A:
The given lines are intersecting at one point so we have one solution.
Part B:
The point of intersection is the solution to the system of equations .In the graph the point of intersection of the lines is (4,4)
Solution is (4,4)
Answer:
c,-0.45 ,
e. 1.16
g. 5/3
h. √2
Cannot be probability.
Step-by-step explanation:
Probability of any occurrence is always in the interval of 0 to 1. 0 and 1 inclusive.
0≤P(A)≤1
Any value outside this boundaries cannot be probability.
Therefore, -0.45,1.16,5/3 and √2 cannot be probability.
9514 1404 393
Answer:
6. step 2; terms are improperly combined; it should be -61n-8=-8
7. no; point (2, 5) is not part of the solution in the left graph
Step-by-step explanation:
6. Step 2 should be ...
-61n -8 = -8 . . . . . because -5n-56n = -61n, not -51n
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7. The boundary lines of both graphs go through the point (2, 5). In the left graph, the line is dashed, indicating that points on the line are not part of the solution set. The point (2, 5) on the dashed line is not a solution to that inequality.
The solid boundary line indicates that the points on the line are part of the solution set. The point (2, 5) on the solid line is a solution to that inequality.
The point (2, 5) is not a solution to both inequalities.
