Answer:
The magnesium atom loses 2 electron to the 2 atoms of chlorine. The 7 valency electrons of each chlorine atom will now be 8 to attain stable configuration. The final compound is written as MgCl2.
Explanation:
Ionic compounds are compound formed from the transfer of electron(s). One atom of the element loses electron(s) while the other atom gains electron(s).
The compound Magnesium chloride is an ionic compound . The bond between an atom of magnesium and 2 atoms of chlorine is an ionic bonding.
The valency electron of magnesium is 2 electron , for the atom of magnesium to attain octet rule, it will easily lose it 2 electrons to the chlorine atoms.
The chlorine atom on the other hand has 7 valency electrons, to attain octet configuration it will most likely gain 1 electron to become stable.
The magnesium atom loses 2 electron to the 2 atoms of chlorine. The 7 valency electrons of each chlorine atom will now be 8 to attain stable configuration. The final compound is written as MgCl2.
Moles of gas = 0.369
<h3>Further explanation</h3>
Given
P = 2 atm
V = 5.3 L
T = 350 L
Required
moles of gas
Solution
Ideal gas Law
Avogadro's law : at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles
moles of O₂ = 45% x 0.369 = 0.166
moles of Ar = 12% x 0.369 = 0.044
moles of N = 43% x 0.369 = 0.159
Molar mass of NaHCO3 is 83.9. moles of Na...O3= 5.8/83.9
=0.0691
for every mole of Na..O3 there are 3 O
n(O) = n(NaHCO3) x3
= 0.207
mass of O is the moles x molar mass (16)
therefore the mass of O is 3.3 grams