Answer:
The second equation can be used
Step-by-step explanation:
Just plug in the values and the equation should look like this 8^2 + b^2 = 12^2
12 is the hypotenuse to plug that into c
and 8 is just a leg so you can either put it in a or b
40 boys and 68 girls
let's start with variables and an equation.
boys: x
girls: 2x - 12
and we know that boys and girls make up the class. so let's add the two expressions.
x + 2x - 12 = 108
3x - 12 = 108
+ 12 + 12
3x = 120
x = 40 boys
BUT x is only the number of BOYS in the class. so we have to find girls now. let's plug in our value of x into the girls' equation.
2x - 12 = # of girls
2(40) -12 = # of girls
80 - 12 = # of girls
68 girls
let's check our answer!
68 + 40 does in fact add to 108, therefore our answer is correct.
Answer:
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Step-by-step explanation:
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Answer:
162.4 in²
Step-by-step explanation:
LETS GET INTOOOOEEETTT
Let's start with what we know:
Area of regular octagon = 1/2 x perimeter x apothem
We know the apothem, so all that we need to find to fill in the above equation is the perimeter:
perimeter = 8 x 5.8 = 46.4in
Now we can fill in our original equation and solve:
Area of regular octagon = 1/2 x perimeter x apothem
Formula = n (s/2)² divided by tan( π /n)
= 8 (5.8/2)² divided by tan ( π /8)
= 162.4283 in²
ORRR when rounded to the nearest tenth,
=162.4 in²
Answer:
The answer is C. AAA is not a congruency postulate because the side lengths may be different sizes although the angles are the same.