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2 years ago

What has to happen for a force to do work on an object?

Physics

1 answer:

dexar [7]2 years ago

4 0

It has to move through a distance over time.

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A tall, open container is full of glycerine. At what depth h below the surface of the glycerine is the pressure 2370 Pa greater

Mice21 [21]

Answer:

So, at the depth of 24 cm below the surface of the glycerine the pressure is 2970 Pa. Hence, this is the required solution.

Explanation:

Given that,

Pressure exerted by the surface of glycerine, P = 2970 Pa and it is greater than atmospheric pressure.

The density of glycerine,

We need to find the depth h below the surface of the glycerine. The pressure due to some depth is given by :

h = 0.24 meters

h = 24 cm

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2 years ago

By counting the number of waves that pass a certain point each second, we will know the _______ of the wave.

Travka [436]

The answer is A. Frequency

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2 years ago

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(6) A

liraira [26]

Answer:

cyguu and I will be like that and I

Explanation:

GHG and I will be like them and I will be like this in the best of luck in the pulley system and the same your time and consideration and I will be like them and I will be like them and I will be like them and TFT capacitive touchscreen and I will be in Phone

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2 years ago

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Two protons move at speed v, one along the x axis and one along the y axis. What is the relative speed of the two protons? Evalu

forsale [732]

Answer:

0.85 c

Explanation:

When the two travel at right angles to each other , their relative velocity is given by the hypotenuse formed by the x and y direction velocities.

Relative velocity of the two protons is given as

$\sqrt{v^{2}+v^{2}} = (\sqrt{2} ) v$

If v = 3/5 c , then the relative speed = $\sqrt{2}$ (3/5c) =0.85 c

8 0

3 years ago

A proton moves through a magnetic field at 26.7 % 26.7% of the speed of light. At a location where the field has a magnitude of

iogann1982 [59]

Answer:

$8.64283\times 10^{-14}\ N$

Explanation:

q = Charge of proton = $1.6\times 10^{-19}\ C$

v = Velocity of proton = $0.267\times c$

c = Speed of light = $3\times 10^8\ m/s$

B = Magnetic field = 0.00687 T

$\theta$ = Angle = $101^{\circ}$

Magnetic force is given by

$F=qvBsin\theta\\\Rightarrow F=1.6\times 10^{-19}\times (0.267\times 3\times 10^8)\times 0.00687\times sin101\\\Rightarrow F=8.64283\times 10^{-14}\ N$

The magnetic force acting on the proton is $8.64283\times 10^{-14}\ N$

4 0

3 years ago