Answer:
After solve the equations we get value of k=3
Step-by-step explanation:
We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.
If the lines are concurrent, they pass through same point.
Let:
First solving equation 1 and 2 to find values of x and y
From eq(1) we find value of x and put it in eq(2)
After solving we get value of y=-1
Now putting in eq(1) to get value of x
So, Value of x= 2
Now put value of x=2 and y=-1 into eq(3) to find value of k
So, After solve the equations we get value of k=3
Answer:
(-∞,0)∪(0,∞)
Step-by-step explanation:
So we know that the domain is whatever X can be. We can do that by graphing the function. When we graph the function, you see that there is always an X value except at 1 point. That one point happens to be when x=0, and when x=0, the function also happens to be undefined (no number can be divided by 0). That is why the graph looks so weird. So, the answer would be
(-infinty,0) U (0, infinity)
Answer:
y = 3.75x+5
Step-by-step explanation:
*** some of your points might be wrong ***
1. Take two points on the line. Ex: (0, 5) and (4, 20)
2. Find the slope using the change in y divided by the change in x.
Ex: m=(20 - 5)/(4 - 0) = 15/4 -> m= 3.75
3. Look at the graph for the y-intercept (when x =0)
y -intercept -> b = 5
Check:
y = mx + b; m = 3.75 (4, 20) -> x= 4 and y =20
20 = 3.75(4) + b
20 = 15 + b
5 = b
4. plug in to slope-intercept form: y = mx +b
y = 3.75x+5
Integration by parts
Integral(udv)=uv-integral(duv)
In this case we will make u=x and dv=8e^(8x) so du=1 and v=e^(8x)
Now integral(8xe^(8x)) => xe^(8x) - integral(e^(8x)) => xe^(8x) - e^(8x)/8 => (e^(8x))(x-1/8)
Final answer:
(E^(8x))(x-1/8) + some constant C
Hope I helped :)
