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2 years ago

Stanley ordered 2 pizzas cut into eighths. if he ate 5/8 of a pizza, how much was left?

Mathematics

2 answers:

Nookie1986 [14]2 years ago

7 0

There was 11/8 of pizza left after Stanley ate.

2 x 8/8 = 16/8
16/8 - 5/8 = 11/8

anastassius [24]2 years ago

4 0

Answer: The required quantity of pizza that was left is $\dfrac{11}{8}.$

Step-by-step explanation: Given that Stanley ordered 2 pizzas cut into eighths and the ate $\dfrac{5}{8}$ of a pizza.

We are to find the quantity of the pizza that was left.

According to the given information, we have

number of pizzas, n = 2

and

the fraction of the pizza ate by Stanley is

$f=\dfrac{5}{8}.$

Therefore, the quantity of pizza that was left is given by

$p_l=n-f=2-\dfrac{5}{8}=\dfrac{2\times8-5}{8}=\dfrac{16-5}{8}=\dfrac{11}{8}.$

Thus, the required quantity of pizza that was left is $\dfrac{11}{8}.$

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(a) $\bar x= 1.583$ -- Population Mean

(b) $s = 1.032$ --- Population standard deviation

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$\sum x = 1.36 + 1.70 + 2.50 + 0.45 + 1.18 + 0.64 + 3.46 + 0.57 + 2.00 + 0.80 + 1.60 +0.98 + 0.36 + 2.24 + 4.35 + 0.62 + 2.70 + 1.78 + 1.53 + 0.84$

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Solving (b): The population standard deviation

This is calculated as:

$s = \sqrt{\frac{\sum( x - \bar x)^2}{n}$

$\sum (x -\bar x)^2 = (1.36 - 1.583)^2 + (1.70 - 1.583)^2+ (2.50 - 1.583)^2+ (0.45 - 1.583)^2+ (1.18 - 1.583)^2+ (0.64 - 1.583)^2+ (3.46 - 1.583)^2+ (0.57 - 1.583)^2+ (2.00 - 1.583)^2+ (0.80 - 1.583)^2+ (1.60 - 1.583)^2+(0.98 - 1.583)^2+ (0.36 - 1.583)^2+ (2.24 - 1.583)^2+ (4.35 - 1.583)^2+ (0.62 - 1.583)^2+ (2.70 - 1.583)^2+ (1.78 - 1.583)^2+ (1.53 - 1.583)^2+ (0.84- 1.583)^2$