Find the sum of the sequence 37+38+39+40+...130
2 answers:
The sum is of37+38+39+40+...130 is 154.13
First, you have to calculate the number in the sequence
an = a+(n-1)d
130 = 27+(n-1)1
130-27 = n-1
103+1 = n
n = 104
Now, calculating for sum (Sn)
Sn = n/2 (a+an) = 104/2 (37+130) = 52 (167) = 8684
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