Which is the 2nd term when 3+2x^2-3x^4+x^3 is Arranged in descending order.

Graph the equation on the coordinate plane.

abruzzese [7]

Solution :

Given, the equation $y=-2x$ .

To graph the equation on the coordinate plane, we first need to derive the different points of the equation $y=-2x$ ,

$at\:\;x=0\Rightarrow y= -2(0)=0\\\\at\:\;x=1\Rightarrow y= -2(1)=-2\\\\at\:\;x=2\Rightarrow y= -2(2)=-4\\\\at\:\;x=3\Rightarrow y= -2(3)=-6\\\\at\:\;x=-1\Rightarrow y= -2(-1)=2\\\\at\:\;x=-2\Rightarrow y= -2(-2)=4\\\\at\:\;x=-3\Rightarrow y= -2(-3)=6$

The graph plotted using these points is shown in the figure,

8 0

2 years ago

Gavin agrees to buy a 6 month package deal of monthly gym passes, and in turn receives a 15% discount. Write an algebraic expres

dolphi86 [110]

15% off means 85% on so I would use .85x · 6 = total monthly cost to represent this problem. The dot represents times (I did not want to confuse things by using x)

Other ways to express this:

6 x .85x
6(.85x)
.85x (6)

4 0

2 years ago

Read 2 more answers

Can you please answer the question?

Roman55 [17]

The <em>trigonometric</em> expression $\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$ is equivalent to the <em>trigonometric</em> expression $\sec \alpha \cdot \csc \alpha + 1$ .

<h3>How to prove a trigonometric equivalence</h3>

In this problem we must prove that <em>one</em> side of the equality is equal to the expression of the <em>other</em> side, requiring the use of <em>algebraic</em> and <em>trigonometric</em> properties. Now we proceed to present the corresponding procedure:

$\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$

$\frac{\tan^{2}\alpha}{\tan \alpha - 1} + \frac{\frac{1}{\tan^{2}\alpha} }{\frac{1}{\tan \alpha} - 1 }$

$\frac{\tan^{2}\alpha}{\tan \alpha - 1} - \frac{\frac{1 }{\tan \alpha} }{\tan \alpha - 1}$

$\frac{\frac{\tan^{3}\alpha - 1}{\tan \alpha} }{\tan \alpha - 1}$

$\frac{\tan^{3}\alpha - 1}{\tan \alpha \cdot (\tan \alpha - 1)}$

$\frac{(\tan \alpha - 1)\cdot (\tan^{2} \alpha + \tan \alpha + 1)}{\tan \alpha\cdot (\tan \alpha - 1)}$

$\frac{\tan^{2}\alpha + \tan \alpha + 1}{\tan \alpha}$

$\tan \alpha + 1 + \cot \alpha$

$\frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{\sin \alpha} + 1$

$\frac{\sin^{2}\alpha + \cos^{2}\alpha}{\cos \alpha \cdot \sin \alpha} + 1$

$\frac{1}{\cos \alpha \cdot \sin \alpha} + 1$

$\sec \alpha \cdot \csc \alpha + 1$

The <em>trigonometric</em> expression $\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$ is equivalent to the <em>trigonometric</em> expression $\sec \alpha \cdot \csc \alpha + 1$ .

To learn more on trigonometric expressions: brainly.com/question/10083069

#SPJ1

6 0

1 year ago

What is the slope of the line passing through the points (2 5) and (-1 -4) show all your work

erastova [34]

Answer:

M=3

(-4 - 5)/(-1-2)

Step-by-step explanation:

Y =3X +-1

4 0

2 years ago

In January 2015, the Pew Research Center reported results from one of their surveys. "Asked about whether vaccines for childhood

scZoUnD [109]

Considering the margin of error, it is found that the 95% confidence interval for the percentage of adults who say vaccines should be required is (64.9%, 71.1%).

<h3>What is a confidence interval?</h3>

It is given by the sample statistic plus/minus the margin of error.

In this problem, 68% of adults say such vaccines should be required, with a margin of error of 3.1%, hence:

68% - 3.1% = 64.9%.

68% + 3.1% = 71.1%.

The 95% confidence interval for the percentage of adults who say vaccines should be required is (64.9%, 71.1%).

More can be learned about confidence intervals at brainly.com/question/25890103

3 0

1 year ago