Please solve the following questions!

Mathematics

1 answer:

polet [3.4K]2 years ago

7 0

Answer:

1.0.008

2.14.06988

3. 0.075

4.21.06

5.66.906

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The length of a room is 4 feet less than twice its width. The perimeter of

AlladinOne [14]

L=2W-4

PERIMETER=2L+2W

58=2(2W-4)+2W

58=4W-8+2W

58=6W-8

6W=58+8

6W=66

W=66/6

W=11 ANS. FOR THE WIDTH.

L=2*11-4

L=22-4

L=18 ANS. FOR THE LENGTH.

PROOF:

58=2*18=2*11

58=36+22

58=58

5 0

2 years ago

Find sin theta if cos theta is 4/5

Dima020 [189]

Answer:

Step-by-step explanation:

hello :

cos²θ +sin²θ = 1 and cosθ =4/5

(4/5)² + sin²θ = 1 so : sin²θ = 1 - 16/25

sin²θ = 9/25 = (3/5)²

sinθ = 3/5 or sinθ = - 3/5 because : (3/5)²= (- 3/5)²= 9/25

5 0

2 years ago

Solve equation by factoring.

3241004551 [841]

Hi ;-)

$x^2+6x-10=30 \ \ /-30\\\\x^2+6x-40=0\\\\a=1, \ b=6, \ c=-40\\\\\Delta=b^2-4ac=6^2-4\cdot1\cdot(-40)=36+160=196\\\\\sqrt{\Delta}=\sqrt{196}=14\\\\x_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-6-14}{2}=\boxed{-10}\\\\x_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-6+14}{2}=\boxed4$