Ask question

Ask question

All categories

2 years ago

6

What is the equivalent resistance between points A and B?

1 answer:

insens350 [35]2 years ago

7 0

All the 3 resistors below point A and B are in series. These 3 resistors can be replaced by an equivalent resistor of resistance R = 1+1+1 = 3 kΩ

Now, this R and 1 kΩ resistor are in parallel because they have common end points. And they can be replaced by an equivalent resistor of resistance
R' = 3x1/3+1 = 3/4

You might be interested in

An 100 kg object traveling at 50 m/s collides (perfectly inelastic) with a 50 kg object initially at rest.

qaws [65]

Answer:

Option C. 5,000 kg m/s

Explanation:

<u>Linear Momentum on a System of Particles </u>

Is defined as the sum of the momenta of each particles in a determined moment. The individual momentum is the product of the mass of the particle by its speed

P=mv

The question refers to an 100 kg object traveling at 50 m/s who collides with another object of 50 kg object initially at rest. We compute the moments of each object

$m_1=(100\ kg)(50\ m/s)=5,000\ kg\ m/s$

$m_2=(50\ kg)(0\ m/s) = 0$

The sum of the momenta of both objects prior to the collision is

$P=5,000\ kg\ m/s+0\ kg\ m/s$

$\boxed{ P=5,000\ kg\ m/s}$

7 0

2 years ago

Your body is receiving backround radiation all the tim. Explain

adoni [48]

The uniform microwave radiation remaining from the Big Bang.

So, your body is always having background radiation and that means space!

3 0

2 years ago

Imagine that the earth and the-moon have positive charges of the same magnitud. How big isäºthe charge necesary to produce an el

lions [1.4K]

Answer:

5.7 x 10^12 C

Explanation:

Let the charge on earth and moon is q.

mass of earth, Me = 5.972 x 10^24 kg

mass of moon, Mm = 7.35 x 10^22 kg

Let d be the distance between earth and moon.

the gravitational force between them is

$F_{g}=G\frac{M_{e} \times M_{m}}{d^{2}}$

The electrostatic force between them is

$F_{e}=\frac{Kq^{2}}{d^{2}}$

According to the question

1 % of Fg = Fe

$0.01 \times 6.67\times10^{-11}\frac{5.97 \times 10^{24}\times7.35 \times 10^{22}}{d^{2}}=9 \times 10^{9}\frac{q^{2}}{d^{2}}$

$2.927 \times 10^{35}=9 \times10^{9}q^{2}$

$3.25 \times 10^{25}=q^{2}$

q = 5.7 x 10^12 C

Thus, the charge on earth and the moon is 5.7 x 10^12 C.

6 0

2 years ago

A car tire rotates with an average angular speed of 32 rad/s. In what time interval will the tire rotate 3.5 times? Answer in un

stiks02 [169]

Answer:

$\Delta t = 0.687\ s$

Explanation:

given,

Angular speed of the tire = 32 rad/s

Displacement of the wheel = 3.5 rev

Δ θ = 3.5 x 2 π

= 7 π rad

now,

Time interval of the car to rotate 7π rad

using equation

$\omega_{avg} =\dfrac{\Delta \theta}{\Delta t}$

$\Delta t=\dfrac{7\pi}{32}$

$\Delta t = 0.687\ s$

Time taken to rotate 3.5 times is equal to 0.687 s.

3 0

2 years ago

Electricity is distributed from electrical substations to neighborhoods at 13000 V. This is a 60 Hz oscillating (AC) voltage. Ne

Levart [38]

Answer:

the number of turns in the primary coil is 13000

Explanation:

Given the data in the question;

V₁ = 13000 V

V₂ = 120 V

N₁ = ?

N₂ = 120 turns

the relation between the voltages and the number of turns in the primary and secondary coils can be expressed as;

V₁/V₂ = N₁/N₂

V₁N₂ = V₂N₁

N₁ = V₁N₂ / V₂

so we substitute

N₁ = (13000 V × 120 turns) / 120 V

N₁ = 1560000 V-turns / 120 V

N₁ = 13000 turns

Therefore, the number of turns in the primary coil is 13000

8 0

2 years ago