[20 POINTS] Can someone help me with question 3 and 4. I’ll mark the correct answer brainliest

By road, without any stopovers, it would take Saad 14 hours and 27 minutes to reach Islamabad from Karachi. He leaves Karachi at

Furkat [3]

Answer:

8:48 p.m.

Step-by-step explanation:

First order half an hour plus 19 minutes used to refuel you will get 49 minutes then add it to the 14 hours 27 minutes you get dinner was 16 minutes then added to the time when he leaves Karachi which is 5:34 am which you get 8:48 p.m.

4 0

2 years ago

Decide which title best describes all of the expressions in each column of the table. Place the correct title at the top of each

irga5000 [103]

For the first one is has greater then 3 terms
The middle one is has exactly one term
And the last one is has two terms
I believe I hope this helps

4 0

2 years ago

C=.41+.26(z-1) solve for z

Ksivusya [100]

$c=0.41+0.26(z-1) \\0.26(z-1)=c-0.41 \\z-1=(c-0.41)/0.26 \\\boxed{z=(c-0.41)/0.26+1}$

Hope this helps.

6 0

2 years ago

the midpoint of AB is point P at (-16,6) if point A is at (-10,8) what are the coordinates of point B?

max2010maxim [7]

Answer:

Denote B(x, y), we have:

-10 + x = 2 x (-16) => x = -22

8 + y = 2 x 6 => y = 4

=> B(-22, 4)

Hope this helps!

:)

8 0

2 years ago

Show that the line 4y = 5x-10 is perpendicular to the line 5y + 4x = 35

Shkiper50 [21]

Step-by-step explanation:

<h2><em><u>concept :</u></em></h2><h2 /><h2><em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.</u></em></h2><h2 /><h2><em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.</u></em></h2><h2 /><h2><em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:</u></em></h2><h2 /><h2><em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:Given equations of lines are</u></em></h2><h2 /><h2><em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:Given equations of lines are4y = 5x-10</u></em></h2><h2 /><h2><em><u>concept :When two lines are perpendicular, then the product of their slopes is equivalent to -1.Equation of line in the form y = mx + c have m as slope of line and c as y-intercept.Solution:Given equations of lines are4y = 5x-10or, y = (5/4)x(5/2).</u></em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>(</em><em>1</em><em>)</em></h2><h2 /><h2><em><u>5y + 4x = 35</u></em></h2><h2 /><h2><em><u>5y + 4x = 35ory = (-4/5)x + 7.</u></em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>(</em><em>2</em><em>)</em></h2><h2 /><h2><em><u>Let m and n be the slope of equations i and ii, respectively.</u></em></h2><h2 /><h2><em><u>Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4</u></em></h2><h2 /><h2><em><u>Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4n= -4/5</u></em></h2><h2 /><h2><em><u>Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4n= -4/5therefore, mx n = -1</u></em></h2><h2 /><h2><em><u>Let m and n be the slope of equations i and ii, respectively.Here, m = 5/4n= -4/5therefore, mx n = -1Hence, the lines are perpendicular.</u></em></h2>

8 0

2 years ago