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2 years ago

(x) = 3x + 5? domain and range

Mathematics

2 answers:

FrozenT [24]2 years ago

5 0

For this case we must find the domain and range of the following function:

$f (x) = 3x + 5$

By definition, the domain is given by all the values for which the function is defined. In this case, the given function is defined for all real numbers. That is to say:

Domain: (-∞,∞)

For its part, the range is the set of values that correspond to the domain. The values that the "y" variable takes. For this function, the range is given by all real numbers.

Range: (-∞,∞)

ANswer:

Domain: (-∞,∞)

Range: (-∞,∞)

kherson [118]2 years ago

4 0

Answer:

Domain is the values that x can take. In terms of real numbers x can take any value and the function will make sense. Since this is linear function the range is not limited too. So the range and domain coincide and are (-infinity;infinity)

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2 years ago

Claire Judice

Julli [10]

Answer:

The values of 'x' are -1.2, 0, 0, $-4i$ or $4i$ .

Step-by-step explanation:

Given:

The equation to solve is given as:

$5x^5+6x^4+80x^3+96x^2=0$

Factoring $x^2$ from all the terms, we get:

$x^2(5x^3+6x^2+80x+96)=0$

Now, rearranging the terms, we get:

$x^2(5x^3+80x+6x^2+96)=0$

Now, factoring $5x$ from the first two terms and 6 from the last two terms, we get:

$x^2(5x(x^2+16)+6(x^2+16))=0\\x^2(x^2+16)(5x+6)=0$

Now, equating each factor to 0 and solving for 'x', we get:

$x^2=0\\x=0\ and\ 0\\\\5x+6=0\\x=\frac{-6}{5}=1.2\\\\x^2+16=0\\x^2=-16\\x=\sqrt{-16}=\pm 4i$

There are 3 real values and 2 imaginary values. The value of 'x' as 0 is repeated twice.

Therefore, the values of 'x' are -1.2, 0, 0, $-4i$ or $4i$ .

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2 years ago

Please Help ASAP!!

Brilliant_brown [7]

Answer:

The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.

Step-by-step explanation:

In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.

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3 years ago

Solve the following equation. Then place the correct number in the box provided.

LuckyWell [14K]

×+6-5=8-2
x+1=6
-1 -1
----------
x=5