In calculus, the squeeze theorem, also known as the pinching theorem, the sandwich theorem, the sandwich rule, the police theorem, the between theorem and sometimes the squeeze lemma, is a theorem regarding the limit of a function. In Italy, the theorem is also known as theorem of carabinieri.
We have to simplify 
%
This is a mixed fraction, with 56 as the whole number part and 
as the fractional part
Such a fraction can be simplified as:
Denominator of simplified fraction = Denominator of mixed fraction
and Numerator of simplified fraction = (Denominator of mixed fraction × Whole number) + (Numerator of simplified fraction)
⇒ Denominator of simplified fraction = 4
and Numerator of simplified fraction = (4 × 56) + (1)
⇒ Numerator of simplified fraction = 225
Hence, the mixed fraction in its simplest form is 
I am assuming 28/0. The short answer is that it is infinity. (Or they may want undefined)
Here is a bit longer explination:
Let's start by taking 28/1, that gives 28. What about 28/0.5 that gives 56, and as we keep decreasing the denominator closer to zero then the quotient will become larger and larger. We we reach zero, the quotient becomes so large that it is considered infinity.
This graph is composed of four straight line segments. You'll need to determine the slope, y-intercept and domain for each of them. Look at the first segment, the one on the extreme left. Verify yourself that the slope of this line segment is 1 and that the y-intercept would be 0 if you were to extend this segment all the way to the y-axis. Thus, the rule (formula, equation) for this line segment would be f(x)=1x+0, or just f(x)=x, for (-3,-1). Use a similar approach to write rules for the remaining three line segments.
Present your answer like this:
x, (-3,-1)
f(x) = -1, (-1,0)
one more here
one more here
Given are the two points (-10,0) and (-8,20), and equation of the line as y=mx+b.
We can plug the given values in the equation as follows :-
0 = -10m + b .........equation(1)
20 = -8m + b .........equation(2)
Subtracting equation(1) from equation(2)
20 - 0 = (-8m + b) - (-10m + b)
20 = -8m + b + 10m - b
20 = 10m - 8m
20 = 2m
m = 10
Plugging m=10 in the equation(1)
0 = -10(10) + b
0 = -100 + b
b = 100
So final answer is b = 100.
