Volume of a cone, V = πr^2h/3
r = Sqrt 3V/πh = Sqrt [(58.9*3)/(3.14*9)] = 2.5 cm, minimum
Surface area, A = πr [r+ Sqrt (h^2+r^2)] = 3.14*2.5*[2.5+ Sqrt (9^2+2.5^2)] = 92.95 cm^2
Therefore, minimum amount of paper required is 92.95 cm^2
It would be “going up a steady rate through the origin”
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Answer:
12.9 square yards
Step-by-step explanation:
The base is an equilateral triangle, so we can assume that the three faces have the same dimensions. Each of those face triangles has an area of ...
A = 1/2bh
A = 1/2(3 yd)(2 yd) = 3 yd²
The base area is computed using the same formula and the given height:
A = 1/2(3 yd)(2.6 yd) = 3.9 yd²
Then the total surface area is that of the base and the three faces:
SA = (3.9 yd²) + 3(3 yd²) = 12.9 yd² . . . total surface area
You will have 40 minutes before it it’s 100% loaded
7(x+4)=0
7x+28=0
7x=-28
X=-28/7
X=-4