to get the equation of any straight line, we simply need two points off of it, so hmmm let's use say (-1 , -1.25) and (8 , -3.5)
Answer:
a) d²y/dx² = ½ x + y − ½
b) Relative minimum
Step-by-step explanation:
a) Take the derivative with respect to x.
dy/dx = ½ x + y − 1
d²y/dx² = ½ + dy/dx
d²y/dx² = ½ + (½ x + y − 1)
d²y/dx² = ½ x + y − ½
b) At (0, 1), the first and second derivatives are:
dy/dx = ½ (0) + (1) − 1
dy/dx = 0
d²y/dx² = ½ (0) + (1) − ½
d²y/dx² = ½
The first derivative is 0, and the second derivative is positive (concave up). Therefore, the point is a relative minimum.
U must find the median, the range, and the mode. And that is your answer
Answer:
what's the question here ?
Answer:
131.3 miles
Step-by-step explanation:
The two cars are moving from different directions. The total distance between the two cars = 118 miles + 256 miles = 374 miles.
Let us assume that the two cars meet at point O, let the distance between car c and O be d₁, the distance between car d and point O be d₂, hence:
d₁ + d₂ = 374 miles (1)
Let speed of car d be x mph, therefore speed of car c = 2x mph (twice of car d). If it take the cars t hours to meet at the same point, hence
For car c:
2x = d₁/t
t = d₁ / 2x
For car d;
x = d₂/t
t = d₂/ x
Since it takes both cars the same time to meet at the same point, therefore:
d₁/2x = d₂ / x
d₁ = 2d₂
d₁ - 2d₂ = 0 (2)
Solving equation 1 and 2 simultaneously gives d₁ = 249.3 miles, d₂ = 124.7 miles
Therefore the distance from point of meet to Boston = 249.3 - 118 = 131.3 miles