You can calculate it using the law of cosines: c^2=a^2+b^2-2*a*b*cos(C)
your triangle is
CD=15=a
CE=?=b
DE=CE+3=b+3=c
and C=90°
-> insert those values, with c substituted with b+3 to remove c
c^2=a^2+b^2-2*a*b*cos(C)
(b+3)^2=15^2+b^2-2*15*b*cos(90)
cos(90)=0->
(b+3)^2=15^2+b^2
b^2+2*3*b+3^2=225+b^2
6b+9=225
6b=216
b=36=CE
DE=CE+3=36+3=39
Answer:
Perimeter=10L
Step-by-step explanation:
The solution is in the image
For graphing the following equations I have my answers as
(-0.5,0.75)
Answer:
2x
Step-by-step explanation:
6x^2
-------
3x
6/3 =2
x^2/x =x*x/x =x
6x^2
------- = 2x
3x