The addison see to the horizon at 2 root 2mi.
We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.
We have to find the how much farther can addison see to the horizon
<h3>Which equation we get from the given condition?</h3>
Where, we have
d- the distance they can see in thousands
h- their eye-level height in feet
For Kaylib
For Addison h=85(1/3)
Subtracting both distances we get
Therefore, the addison see to the horizon at 2 root 2mi.
To learn more about the eye level visit:
brainly.com/question/1392973
Answer: 2,580
Step-by-step explanation:
215,000 x .012 = 2,580
4/81 (?)
not sure if that is 100% correct
Answer:
174
Step-by-step explanation:
L = 68
W=19
Use the formula given:
2 x 68 + 2 x 19 = 174
Answer:
X=17
Step-by-step explanation:
AC^2=AB^2 +BC^2(PYTHAGOREAN THEORM)
100=64 +BC^2
36=BC^2
6CM=BC
AD^2=AB^2+BD^2(PYTHAGOREAN THEORM)
X^2 =64+225
X^2=289
X=17