The base area of this second rectangular prism is 51 cm²
The rectangular prism completely filled with sand has a base area of 85cm² and height of 15cm .
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volume of a rectangular prism</h3>
where
B = base area
h = height
Since the first rectangular prism was completely filled with sand and it completely filled the second rectangular prism, it means they both have the same volume.
Therefore,
volume of the first rectangular prism = volume of the second rectangular prism.
Therefore, the base area of the second rectangular prism can be calculated as follows:
volume = Bh
1275 = 25B
B = 1275 / 25
B = 51 cm²
learn more on prism here: brainly.com/question/2517494?referrer=searchResults
Answer:
The statements that must be true are:
XY and JK form four right angles ⇒ B
XY ⊥ JK ⇒ C
JP = KP ⇒ E
m∠JPX = 90° ⇒ F
Step-by-step explanation:
From the given figure
∵ Line XY is the perpendicular bisector of the line segment JK
→ That means line XY is the line of symmetry of the line segment JK
∴ XY ⊥ JK ⇒ C
∵ XY ∩ JK at point P
∴ P is the midpoint of JK
∵ XY ⊥ JK
∴ ∠JPX, ∠KPX, ∠JPY, and ∠KPY are right angles
∴ XY and JK form four right angles ⇒ B
∵ The measure of the right angle is 90°
∴ m∠JPX = m∠KPX = m∠JPY = m∠KPY = 90°
∴ m∠JPX = 90° ⇒ F
∵ P is the midpoint of JK
∴ JP = KP ⇒ E
Answer:
Sometimes true, because x could be anything
Step-by-step explanation:
Answer:
The proportion of the offspring from the cross PpRr × PpRr that are expected to have white flowers and wrinkled seeds is 1/16 or 6.25%.
Step-by-step explanation:
The uppercase letter represents the dominant allele, while the lowercase represents the recessive allele. The dominant allele determines the phenotype (observable trait) when it is present.
When you cross heterozygous individuals for each trait, each individual of the offspring has the probability of 1/6 of each combination of four alleles (two for each trait). Because the dominant allele determines the phenotype when it is present, the probability of dominant phenotypes is higher than recessive phenotypes.
Proportions of each phenotype in the offspring from the cross PpRr × PpRr are:
Purple flowers with round seeds: 9/16
Purple flowers with wrinkled seeds: 3/16
White flowers with round seeds: 3/16
White flowers with wrinkled seeds: 1/16
The proportion of individuals with white flowers and wrinkled seeds is the lowest because they are homozygous recessive for both traits.
Idk I just need to answer some more questions