I had to take a screenshot of my response since it was getting flagged for being inappropriate for some reason.
The answer to this question is B. Yy and has yellow seeds
After two half-lives or 60 years, 7.5 g of the element will be left.
<u>Explanation:</u>
<u>Half-life:</u>
- In simple words, Half-life can be defined as the amount of time needed for a quantity to fall to half its value as contained at the beginning of the time period.
- In this problem the half-life of the element is thirty years, then after thirty years half of the sample would have decayed and half would be left as it is.
- After thirty years (The first half-life ) 30 /2 = 15 g declines and 15 g remains disappeared.
- And after another sixty years (The two half-lives) 15 /2 = 7.5 g declines and 7.5 g remains disappeared.
- After two half-lives or 60 years, 7.5 g of the element will be left.
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The sucrose move in source to sieve by active transport.
<h3>What is active transport?</h3>
Active transport is a type of transport in which the cell expends energy to move solutes against their concentration gradients. The sodium-potassium pump is an example of active transport. Active transport differs from passive transport in that the cell does not expend energy.
In this case, the sucrose moves from companion cells into source to sieve elements by active transport. This reduces the water potential of the source to sieve element by osmosis, which increases the hydrostatic pressure.
See more about sucrose at brainly.com/question/24214907
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