Answer:
21.5
Step-by-step explanation:
19^2+10^2=461
square root of 461 =21.47091055
round to the nearest tenth to get 21.5
Answer:
see explanation
Step-by-step explanation:
To find the x- intercept let y = 0 in the equation and solve for x
x + 0 = 9
x = 9 ← x- intercept ⇒ (9, 0 )
To find the y- intercept let x = 0 in the equation and solve for y
0 + y = 9
y = 9 ← y- intercept ⇒ (0, 9 )
<h3>Answer:</h3>
87.5 ounces
<h3>Explanation:</h3>
There's a cute "X-diagram" tool that can be used for solving mixture problems of all kinds. (See the attachment.) The numbers on the left represent the percentages of the constituents of the mix. The number in the center is the desired percentage in the resultant mix. The numbers on the right in the X are the differences along the diagonals. (6-5=1, 5-3=2)
These are also the proportions of the constituents in the final mix. That is, there are 2 parts of spice that is 6% salt for each 1 part of spice that is 3% salt. So, we need half as much of the latter as the former.
Half of 175 ounces is 87.5 ounces, the amount of 3% spice that is needed.
_____
If you really want to write an equation, you can let x represent the amount of 3% spice needed. Then the amount of salt in the mix is ...
... 175×6% +x×3% = (175+x)×5%
Dropping the percent symbols and eliminating parentheses, we have
... 1050 +3x = 875 +5x
... (1050 -875) = (5x -3x) . . . . . add -875-2x
... 175/2 = x = 87.5 . . . . . . . . . . divide by the coefficient of x
If one basket is selected at random, the probability that both are mangoes is; 1/10
<h3>How to find probabilities?</h3>
Contents of first basket;
3 mangoes
4 oranges
3 apples
Contents of second basket;
5 mangoes.
5 oranges.
5 apples.
Probability of mango in first basket is = 3/10
Probability of mango in second basket is = 5/15
Thus;
Probability that both are mangoes = (3/10) * (5/15)
Probability that both are mangoes = 1/10
Read more about Probabilities at; brainly.com/question/24756209
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Answer:
(f+g)(x)=5x-4
(f*g)(x)=(4x^2-19x-5)
(f-g)(3)=(-15)
Step-by-step explanation:
(f+g)(x)=(x-5)+(4x+1)=(5x-4)
(f*g)(x)=(x-5)(4x-1)=(4x^2-19x-5)
(f-g)(3)=(x-5)-(4x-1)=(3-5)-(4(3)+1)=(-2)-(12+1)=(-2)-(13)=-15 substitute 3 for x