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2 years ago

What is the distance between point A (-2 , -1) and point B (3, 2)?

Mathematics

1 answer:

lana [24]2 years ago

4 0

Answer:

Distance = √34

Step-by-step explanation:

Using the formula for distance

d = √(x_2 - x_1)^2 + ( y_2 - y_1)^2

Using what we are provided with

Two points

( -2, -1)(3, 2)

x_1 = -2

y_1 = -1

x_2 = 3

y_2 = 2

Inserting the values

d = √ ( 3 -(-2)^2 + (2-(-1)^2

= √ (3+2)^2 + (2+1)^2

= √ 5^2 + 3^2

= √25 + 9

= √34

= 5.83

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2 years ago

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2 years ago

The exam scores for 200 students are normally distributed with a mean of 72 and a standard deviation of 10. Which answer choice

Paha777 [63]

Using the normal distribution, it is found that there are 68 students with scores between 72 and 82.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

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The proportion of students with scores between 72 and 82 is the <u>p-value of Z when X = 82 subtracted by the p-value of Z when X = 72</u>.

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X = 72:

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Out of 200 students, the number is given by:

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More can be learned about the normal distribution at brainly.com/question/24663213

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