A beaker of vegetable oil contains a beam of light that is aimed at a surface at an angle of 34 degrees as shown. If the index o
ff refraction of the oil is 1.47, what is the angle of reflection?
1 answer:
Answer:
Angle of reflection of light is 34 degree
Explanation:
As per law of reflection of light we know that
angle of incidence of light = angle of reflection of light
So here we know that
angle of incidence on the surface of oil is given as
so we know that
so here we can say that reflection angle of light will be same as angle of incidence
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Answer:
Explanation:
In a uniform circular motion, since a complete revolution represents 2π radians, the angular velocity, which is defined as the angle rotated by a unit of time, is given by:
Here T is the period, that is, the time taken to complete onee revolution:
Replacing (2) in (1):
Answer:
A) 2.75 m/s B) 0.1911 m C) 0.109 s
Explanation:
mass of block = M =0.1 kg
spring constant = k = 21 N/m
amplitude = A = 0.19 m
mass of bullet = m = 1.45 g = 0.00145 kg
velocity of bullet = vᵇ = 68 m/s
as we know:
Angular frequency of S.H.M = ω₀ =
=
= 14.49 rad/sec
<h3>A) Speed of the block immediately before the collision:</h3>displacement of Simple Harmonic Motion is given as:
Differentiating this to find speed of the block immediately before the collision:
As bullet strikes at equilibrium position so,
φ = 0
t= 2nπ
⇒ cos (ω₀t + φ) = 1
⇒
S.H.M after collision is given as :
To find B, consider law of conservation of energy
Time period S.H.M is given as:
Collision occurred at equilibrium position so time taken by block to reach maximum amplitude is equal to one fourth of total time period