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steposvetlana [31]

2 years ago

9

Define in own words.

1 answer:

professor190 [17]2 years ago

8 0

A recurring illness or an illness that lasts for a long time. Chronic illnesses are typically very hard to cure.

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How do you write a scale for distance-time graph in physics?

Studentka2010 [4]

Answer:

Time always is on X axis.

8 0

2 years ago

Read 2 more answers

Water with a volume flow rate of 0.001 m3/s, flows inside a horizontal pipe with diameter of 1.2 m. If the pipe length is 10m an

galben [10]

Answer:

$\triangle P=1.95*10^{-4}$

Explanation:

Mass $m=0.001$

Diameter $d=1.2m$

Length $l=10m$

Generally the equation for Volume flow rate is mathematically given by

$Q=AV$

$V=\frac{Q}{\pi/4D^2}$

$V=\frac{0.001}{\pi/4(1.2)^2}$

$V=8.84*10^{-4}$

Generally the equation for Friction factor is mathematically given by

$F=\frac{64}{Re}$

Where Re

Re=Reynolds Number

$Re=\frac{pVD}{\mu}$

$Re=\frac{1000*8.84*10^{-4}*1.2}{1.002*10^{-3}}$

$Re=1040$

Therefore

$F=\frac{64}{Re}$

$F=\frac{64}{1040}$

$F=0.06$

Generally the equation for Friction factor is mathematically given by

$Head loss=\frac{fLv^2}{2dg}$

$H=\frac{0.06*10*(8.9*10^-4)^2}{2*1.2*9.81}$

$H=19.9*10^{-9}$

Where

$H=\frac{\triangle P}{\rho g}$

$\triangle P=\frac{19.9*10^{-9}}{10^3*(9.81)}$

$\triangle P=H*\rho g$

$\triangle P=1.95*10^{-4}$

6 0

2 years ago

If you weigh 120 pounds on earth what is your weight on the moon

rusak2 [61]

Moons gravity is about 1/6 as powerful as it is on Earth, so about 20 pounds.

8 0

2 years ago

an airplanes propeller completes one revolution in 65ms. a)what is the angular speed in rpm? in rad/s?

miss Akunina [59]

-- We already know the rate of revolutions per time ...
it's 1 revolution per 0.065 sec. We just have to
unit-convert that to 'per minute'.

(1 rev / 0.065 sec) x (60 sec / min) = (1 x 60) / (0.065) = <em>923 RPM</em> (rounded)
_______________________________

-- 1 revolution = 2π radians

(2π rad) / (0.065 sec) = (2π / 0.065) = <em>96.66 rad/sec</em> (rounded)

7 0

2 years ago

A point charge Q is placed at the center of a cube of side l. what is the flux through one face of the cube?

dimaraw [331]

Answer:

$\phi=\dfrac{q}{6\epsilon_o}$

Explanation:

A point charge Q is placed at the center of a cube of side l.

We need to find the flux through one face of the cube. Let the flux is $\phi$ .

There are 6 faces in a cube.

According to Gauss's law, net flux is given by :

$\phi=\dfrac{q}{\epsilon_0}$

As there are 6 faces of a cube, flux through one surface is :

$6\phi=\dfrac{q}{\epsilon_o}\\\\\phi=\dfrac{q}{6\epsilon_o}$

So, the flux through one face of the cube is $\dfrac{q}{6\epsilon_o}$ .

8 0

2 years ago