A force of 660 n stretches a certain spring a distance of 0.300 m. what is the potential energy of the spring when a 70.0 kg mas
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The bullet is moving by uniformly accelerated motion.
The initial velocity is
, the final velocity is 
, and the total time of the motion is 
, so the acceleration is given by
where the negative sign means that is a deceleration.
Therefore we can calculate the total distance covered by the bullet in its motion using
So, the bullet penetrates the sandbag 1.8 meters.
The bullet is moving by uniformly accelerated motion.
The initial velocity is
where the negative sign means that is a deceleration.
Therefore we can calculate the total distance covered by the bullet in its motion using
So, the bullet penetrates the sandbag 1.8 meters.
Answer:
Explanation:
To develop this exercise we proceed to use the kinetic energy equations,
In the end we replace
Here
meaning the 4 wheels,
So replacing
So,
Answer:
V = 0.0723 volts = 72.3 milivolts
Explanation:
The emf induced in the rod is the motional emf due to the magnetic field. This motional emf can be calculated by the following formula:
where,
V = Motional EMF = ?
v = speed of rod = 12.5 m/s
B = Magnetic Field = 6.23 mT = 0.00623 T
l = Length of rod = 92.9 cm = 0.929 m
θ = angle between v and B = 90°
Therefore,
<u>V = 0.0723 volts = 72.3 milivolts</u>