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2 years ago

PLZ HELP ASAPP!!!!

Mathematics

1 answer:

juin [17]2 years ago

4 0

Answer:

It is

Step-by-step explanation:

52² = 20² + 48²

2704 = 400 + 2304

2704 = 2704

Satisfies pythagoras theorem so right angle triangle

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Three minus the quotient of a number x and 12

attashe74 [19]

Answer:

3 - x/12

Step-by-step explanation:

follow the steps in the sentence

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2 years ago

Ram travels 200 km in 2 and a half hours by a car, how long would he take to travel 140

MrRissso [65]

Answer:

x=1.75 hour

Step-by-step explanation:

200km=2.5

140km=x

2.5 * 140=200x

350=200x

x=350/200

x=1.75

the time it will take is x=1.75 hour

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2 years ago

OMG I'M LITERALLY CRYING PLS HELP!!!!

zepelin [54]

The answer would be $25.22 the way to do this would be to divide 7.76 by 4 and then you would multiply that answer by 13 so it would be the 4th answer

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2 years ago

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Six numbers that are not perfect cubes

Natalka [10]

Six numbers that are not perfect cubes 43, 0, 61, 15, 14, and 3

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2 years ago

Match each spherical volume to the largest cross sectional area of that sphere

zlopas [31]

Answer:

Part 1) $324\pi\ units^{2}$ ------> $7,776\pi\ units^{3}$

Part 2) $36\pi\ units^{2}$ ------> $288\pi\ units^{3}$

Part 3) $81\pi\ units^{2}$ ------> $972\pi\ units^{3}$

Part 4) $144\pi\ units^{2}$ ------> $2,304\pi\ units^{3}$

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

$A=324\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$324\pi=\pi r^{2}$

Solve for r

$r^{2}=324$

$r=18\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=18\ units$

substitute

$V=\frac{4}{3}\pi (18)^{3}$

$V=7,776\pi\ units^{3}$

Part 2) we have

$A=36\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$36\pi=\pi r^{2}$

Solve for r

$r^{2}=36$

$r=6\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=6\ units$

substitute

$V=\frac{4}{3}\pi (6)^{3}$

$V=288\pi\ units^{3}$

Part 3) we have

$A=81\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$81\pi=\pi r^{2}$

Solve for r

$r^{2}=81$

$r=9\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=9\ units$

substitute

$V=\frac{4}{3}\pi (9)^{3}$

$V=972\pi\ units^{3}$

Part 4) we have

$A=144\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$144\pi=\pi r^{2}$

Solve for r

$r^{2}=144$

$r=12\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=12\ units$

substitute

$V=\frac{4}{3}\pi (12)^{3}$

$V=2,304\pi\ units^{3}$

5 0

2 years ago

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