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3 years ago

Are natural numbers always sometimes never rational numbers

1 answer:

7 0

Natural numbers are always rational numbers,

Rational numbers can be defined as numbers that can be represented as a ratio of two integers. All natural numbers can be represented as a ratio because theycan be over one. For example, 3/1 or 19838645752641/1.

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Find AA and BB that make the equation true. Verify your results.

CaHeK987 [17]

Answer:

a. A = -1 and B = 1

b. A = 7 and B = -5

Step-by-step explanation:

$\frac{A}{x+1} +\frac{B}{x-1} = \frac{2}{x^2-1}$

$\frac{A*(x-1)+B*(x+1)}{(x+1)*(x-1)} = \frac{2}{x^2-1}$

$\frac{Ax - A + Bx + B}{x^2 -1} = \frac{2}{x^2-1}$

To the equation be true, the "x-parts" and "nonx-parts" mist be the same, so:

Ax + Bx = 0

(A + B)x = 0

A + B = 0

A = -B

B - A = 2

B - (-B) = 2

2B = 2

B = 1 and A = -1

$\frac{A}{x+3} + \frac{B}{x +2} = \frac{2x -1}{x^2+5x+6}$

$\frac{A*(x+2) + B*(x+3)}{(x+3)*(x+2)} = \frac{2x-1}{x^2+5x+6}$

$\frac{Ax + 2A + Bx + 3B}{x^2 + 5x + 6} = \frac{2x-1}{x^2+5x+6}$

To the equation be true, the "x-parts" and "nonx-parts" mist be the same, so:

Ax + Bx = 2x

(A + B)x = 2x

A + B = 2

A = 2 - B

2A + 3B = -1

2*(2-B) + 3B = -1

4 - 2B + 3B = -1

B = -5 and A = 2 - (-5) = 7

5 0

2 years ago

What happens if you subtract the two equations and solve for S5? Can you use this information to come up with a way to find any

bulgar [2K]

Step-by-step explanation:

¿Puedes decirnos las ecuaciones?

6 0

2 years ago

AHHH URGENT ANSWER QUICK I GIVE BRAINLIEST

Step2247 [10]

Answer:

20/54

Step-by-step explanation:

5 0

2 years ago

A certain forest covers an area of 2900 km. Suppose that each year this area decreases by 8.5%. What will the area be after 8 ye

Ann [662]

Answer:

1425 square kilometer.

Step-by-step explanation:

2900 - 8.5% = 2653.5

2653.5 - 8.5% = 2427.9525

2427.9525 - 8.5% = 2221.5765375

2221.5765375 - 8.5% = 2032.74253181

2032.74253181 - 8.5% = 1859.95941661

1859.95941661 - 8.5% = 1701.8628662

1701.8628662 - 8.5% = 1557.20452257

1557.20452257 - 8.5% =1 424.84213815 ≈ 1425

3 0

2 years ago

Read 2 more answers

Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim

vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

$2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}$

Dividing we get,

$2 { h } 54 \text { min }=2 \mathrm{h}+0.9 {h}$

Adding, we have,

$2 { h } 54 \text { min }=2.9 {h}$

Thus, the total time taken by Joshua is $2.9 {h}$

To determine the average speed we use the formula,

$speed=\frac{distance}{time}$

where $distance=7250$ and $time=2.9$

Hence, substituting the values we have,

$speed=\frac{7250}{2.9}$

Dividing, we get,

$speed=2500$

Thus, the average speed of Joshua during that time is 2500 m/h.

5 0

2 years ago