2.0kg and the mass of sometimes makes it hard 2.8kg
Answer:
The initial speed of the ball is 30 m/s.
Explanation:
It can be assumed that the ball is thrown at an angle of 45 degrees to the ground. The ball lands 90 m away. We need to find the initial speed of the ball. We know that the horizontal distance covered by the projectile is called its range. It is given by :
u is the initial speed of the ball.
v = 29.69 m/s
or
v = 30 m/s
So, the initial speed of the ball is 30 m/s. Hence, this is the required solution.
Answer:
Y = 0.0254 m = 25.4 mm
Explanation:
The formula for the fringe spacing in Young's Double-slit experiment is given by the following formula:
where,
Y = fringe spacing = 0.0176 m
λ = wavelength = 425 nm = 4.25 x 10⁻⁷ m
L = Distance between screen and slits
d = slit separation
Therefore,
Now, for:
λ = 614 nm = 6.14 x 10⁻⁷ m
<u>Y = 0.0254 m = 25.4 mm</u>
Answer:
Explanation:
radius of the solenoid, r = 0.05 m
length of the solenoid, l = 0.39 m
Magnetic field of the solenoid, B = 2 x 10^-5 T
Number of turns, N = 200
The magnetic field of the solenoid is given by
where, i be the current and n be the number of turns per unit length
n = N / l = 200 / 0.39 = 512.8
i = 0.031 A