draw a rectangle around it:
the widest part is from about -3 to 2 which is 5 units wide
height is from 3 to -4, which is 7 units
5*7 = 35
the top and bottom are angled so you can subtract a little for that
so I would estimate around 32 square units
I believe the answer would be B
Answer:
The value of the snack bar is $ 2 and that of the magazine subscription is 25 $
Step-by-step explanation:
We have a system of two equations and two unknowns, which would be the following:
let "x" be the cost of the snack bar
Let "y" be the cost of the magazine subscription
16 * x + 4 * y = 132
20 * x + 6 * y = 190 => y = (190 - 20 * x) / 6
replacing:
16 * x + 4 * (190 - 20 * x) / 6 = 132
16 * x + 126.66 - 13.33 * x = 132
2.66 * x = 132 - 126.66
x = 5.34 / 2.66
x = 2
for "y":
y = (190 - 20 * 2) / 6
y = 25
Which means that the value of the snack bar is $ 2 and that of the magazine subscription is 25 $
The probability of choosing a number that is not a multiple of 2 is P = 0.44
<h3 /><h3>How to find the probability?</h3>
We need to count the number of options for each digit.
- For the first digit, we have 8 options {1, 2, 3, 4, 5, 6, 7, 8}
- For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
- For the third digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}.
The total number of combinations is the product between the numbers of options:
C = 8*9*9 = 648
If we want our number to not be a multiple of 2 then it must end in a odd digit, the combinations that meet that condition are:
- For the first digit, we have 8 options {1, 2, 3, 4, 5, 6, 7, 8}
- For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
- For the third digit, we have 4 options {1, 3, 5, 7}.
C = 8*9*4 = 288
Then the probability of selecting a 3 digit number that is not a multiple of 2 is:
P = 288/648 = 0.44
If you want to learn more about probability, you can read:
brainly.com/question/251701
