Urn 1 = 4 green balls and 6 blue balls, a total of 10 balls
Urn 2 = 6 green balls and 2 blue balls, a total of 8 balls.
Probability of blue balls:
Urn 1 : P = 6/10
Urn 2 : P = 2/8
Probability that both balls are blue:
6/10 * 2/8 = 6*2 / 10*8 = 12/80 = 6/40 = 3/20
Answer is B. 3/20
Perimeter of a rectangle: 2(l+w)
Let width be 'x'
Length is 3 meters more than twice 'x'
Length= 2x+3.
L= x
W = 2x+3
Formula =
2(x+2x+3)
2(3x+3)
6x+6.
6(x+1)
10000 digits can be used for 4 digit A.T.M code.
<u>Solution:</u>
Given that A.T.M required 4 digit codes using the digits 0 to 9.
Need to determine how many four digit code can be used.
We are assuming that number starting with 0 are also valid ATM codes that means 0789 , 0089 , 0006 and 0000 are also valid A.T.M codes.
Now we have four places to be filled by 0 to 9 that is 10 numbers
Also need to keep in mind that repetition is allowed in this case means if 9 is selected at thousands place than also it is available for hundreds, ones or tens place .
First digit can be selected in 10 ways that is from 0 to 9.
After selecting first digit, second digit can be selected in 10 ways that is 0 to 9 and same holds true for third and fourth digit.
So number of ways in which four digit number is created = 10 x 10 x 10 x 10 = 10000 ways
Hence 10000 digits can be used for 4 digit A.T.M code.
What is the question?????
Answer:4hrs per dollar
Step-by-step explanation:
$12=3hrs
? =1hr
12*1/3
=4
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