I think it would be linear . if its not right then im sorry .
is differentiable across its domain, so the MVT says there is some value of
in the open interval
such that
You have
so the equation above becomes
Solve for
.
so
is indeed the average of the endpoints, i.e. the midpoint.
Answer:
14m-5-8m
Step-by-step explanation:
Answer:
-40 square root of 10k²
Step-by-step explanation: