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2 years ago

Represent 240.149 in two different ways

Mathematics

1 answer:

choli [55]2 years ago

8 0

Answer:

240 149/1000, 240149/1000

Step-by-step explanation:

Mixed Number, Improper Fraction

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-24.5 divided by 6.5

liberstina [14]

Answer:

-3.7

Step-by-step explanation:

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2 years ago

Which triangles can not be proved congruent?#37

soldi70 [24.7K]

B is the answer because it does not give information for the third side. We cannot assume it is equal because it is not a right triangle.

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2 years ago

What is the value of x in the model below? <br> Enter your answer in the box.

sp2606 [1]

It looks like the scale is balanced so that means you can set one side equal to the other which leaves you with the equation x+(-10)=-16

To get x by itself add x to each side to get x=-6

X=-6 is your answer

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3 years ago

Read 2 more answers

You spin the spinner twice. Find the probability of the event.<br><br> Spinning a 3 and then 4

olga nikolaevna [1]

Answer:

The answer is 1/36

Step-by-step explanation:

each event has a 1/6 chance of happening so you multiply 1/6 by 1/6 and get 1/36

3 0

2 years ago

A large tank is filled to capacity with 600 gallons of pure water. brine containing 4 pounds of salt per gallon is pumped into t

nignag [31]

If $A(t)$ is the amount of salt in the tank at time $t$ , then the rate at which the amount of salt in the tank changes is given by

$\dfrac{\mathrm dA(t)}{\mathrm dt}=\dfrac{4\text{ lbs}}{1\text{ gal}}\dfrac{6\text{ gal}}{1\text{ min}}-\dfrac{A(t)\text{ lbs}}{600\text{ gal}}\dfrac{6\text{ gal}}{1\text{ min}}$
$\dfrac{\mathrm dA}{\mathrm dt}=24\dfrac{\text{lb}}{\text{min}}-\dfrac{A(t)}{100}\dfrac{\text{lb}}{\text{min}}$

Let's drop the units for now. We have

$\dfrac{\mathrm dA(t)}{\mathrm dt}+\dfrac{A(t)}{100}=24$
$e^{t/100}\dfrac{\mathrm dA(t)}{\mathrm dt}+e^{t/100}\dfrac{A(t)}{100}=24e^{t/100}$
$\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/100}A(t)\right]=24e^{t/100}$
$e^{t/100}A(t)=\displaystyle24\int e^{t/100}\,\mathrm dt$
$e^{t/100}A(t)=2400e^{t/100}+C$
$A(t)=2400+Ce^{-t/100}$

We're given that the water is pure at the start, so $A(0)=0$ , giving

$A(0)=0=2400+Ce^{-0/100}\implies C=-2400$

So the amount of salt in the tank (in lbs) at time $t$ is

$A(t)=2400\left(1-e^{-t/100}\right)$

4 0

2 years ago