If 945 is the product of 5 CONSECUTIVE ODD numbers, let's find the prime factors of 945:
945 = 5 x 7 x 27 , but we need 5 odd numbers:
945= 5 x 7 x ( 3 x 9 ) we still need one factor. This factor cannot be but 1
945 = 1 x 3 x 5 x 7 x 9 = 945 and the greatest value of these integers is 9
Correct question:
a sequence U1, U2,U3...... is defined by the relation . if U1 =2, find U2 and U3
Answer:
U2 = 9
U3 = 23
Step-by-step explanation:
Given sequence;
U1 = 2
U2 = ?
Solving for U3;
Answer:
$5.25 Dollars
Step-by-step explanation:
I know that if you divide 21 by 3 you get 7. So, 2/3 of 21 is 14. He spent 14 dollars at the music store. This means that he has 7 dollars left. From here he spend 1/4 of 7 dollars on a drink. 1/4 of 7 is $1.75. This means that he has 5.25 dollars left after he bought the drink! :)
<em>Hope this helped! :)</em>
Low-birthweight i believe.
Since we know that a number is divisible by 3 if the sum of all digits is divisible by 3.
Let us check which digits will make 371? divisible by 3.
11 is not divisible by 3.
Now let us check other digits as well.
12 is divisible by 3.
15 is also divisible by 3.
18 is divisible by 3 as well.
Therefore, 1, 4 and 7 in tenth place will make our number divisible by 3 and our numbers will be 3711, 3714 and 3717.