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2 years ago

7

A brick measures 25 cm by 12 cm by 13 cm. What is the volume of the brick in cm3? How many milliliters of water would this brick

displace?

1 answer:

hodyreva [135]2 years ago

7 0

Volume is lxwxh so do 25x12x13

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An isotope contains 26 protons, 24 electrons, and 32 neutrons.

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26
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2 years ago

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Identify all the physical properties of a base.

KiRa [710]

Answer:

Bases are ionic compounds that produce negative hydrogen ions (OH⁻) when dissolved in water.
An example of a base is Sodium Hydroxide (NaOH).
Bases have a bitter taste.
Bases feel slippery.
Bases conduct electricity when dissolved in water.
Bases change litmus paper from red to blue in colour.
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Hope this helps!

7 0

2 years ago

What are the three broad classes of elements

mario62 [17]

The three broad classes of elements are:

Metals
Metalloids
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4 0

2 years ago

A reaction produces 0.801 moles of H2O. How many molecules of H20 are produced?

timama [110]

Answer:

1 mole of molecules = 6.022 × 10²³ molecules

1 = 6.022 × 10²³ molecules / mole

Multiplying a number with [6.022 × 10²³ molecules / mole] is like multiplying the number with 1 so 0.877 mole × 6.022 × 10²³ molecules / mole = 5.28 × 10²³ molecules

5.28 × 10²³ molecules of water is produced.

Explanation:

6 0

1 year ago

A certain reaction has an activation energy of 66.41 kJ/mol. At what Kelvin temperature will the reaction proceed 3.00 times fas

swat32

Answer : The temperature will be, 392.462 K

Explanation :

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $T_1$ = $K_1$

$K_2$ = rate constant at $T_2$ = $3K_1$

$Ea$ = activation energy for the reaction = 66.41 kJ/mole = 66410 J/mole

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 293 K

$T_2$ = final temperature = ?

Now put all the given values in this formula, we get:

$\log (\frac{3K_1}{K_1})=\frac{66410J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{293K}-\frac{1}{T_2}]$

$T_2=392.462K$

Therefore, the temperature will be, 392.462 K

8 0

2 years ago