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Answer:
65.3658 inches
Step-by-step explanation:
Let X be the height of a woman randomly choosen. We know tha X have a mean of 63.6 inches and a standard deviation of 2.5 inches. For an x value, the related z-score is given by z = (x-63.6)/2.5. We are looking for a value such that , but, , i.e., is the 76th percentile of the standard normal distribution. So, , . Therefore, the height of a woman who is at the 76th percentile is 65.3658 inches.
I think it is 21 and 50. The only common factor they have is 1.
All the others are divisible by 1 & 3.
The answer is 492.307
The number after the thousandths is 9 - greater than 5 - so we round 6 up to 7.
546 - 525 = 21
21 is 4% of 525.
Lisa gained a 4% pay increase.