<u>Answer-</u>
Set of constraints to model the problem are,
<u>Solution-</u>
Let us assume,
x = the number of lawns weeded by Gwen,
y = the number of dogs walked by Fabio.
Gwen charges $12 each time she weeds a yard and Fabio charges $9 each time he walks a dog,
They need at least $510 to purchase the new gaming station, means they need $510 or more than $510.
An equation for this situation will be,
The number of dog walked by Fabio has scheduled is no more than twice the number of yards Gwen has scheduled to weed, means y must be less than or equal to 2x.
An equation for this situation will be,
Fabio will walk at least 25 dogs, means y must be greater than of equal to 25.
An equation for this situation will be,
Answer:
y= x2 + 8x - 1 is y=(x+4) 2-17
Step-by-step explanation:
First find - b/2 = - 4, so -4 will be added to x inside the parenthesis.
Next , find c - b2 to find the value you added at the end
y= (x- b2) 2 + c - b2
y= (x+4) 2 - 17
Answer:
2 .The slope of Function A is less than the slope of Function B
Step-by-step explanation:
A graph of Function A shows it has a y-intercept of 4, the same as that of Function B. (Statements 3 and 4 are not correct.)
The slope of Function A is 2, which is less than the slope of 3 that Function B has. (Statement 2 is correct; statement 1 is not.)
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<em>More detailed working</em>
The slope of Function A can be figured easily between the points with x-values that differ by 1:
m = (y3 -y2)/(x3 -x2) = (24-22)/(10-9) = 2/1 = 2 . . . . . Fun A has slope of 2.
The slope of Function B is the coefficient of x in the equation: 3.
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The y-intercept of Function A can be found starting with point-slope form:
y -22 = 2(x -9)
y = 2x -18 +22
y = 2x +4 . . . . . . . slope-intercept form
The intercept of +4 is the same as that of Function B.
Answer:
x = 0
, y = 4
Step-by-step explanation:
Solve the following system:
{y = 4 - 3 x | (equation 1)
x + 2 y = 8 | (equation 2)
Express the system in standard form:
{3 x + y = 4 | (equation 1)
x + 2 y = 8 | (equation 2)
Subtract 1/3 × (equation 1) from equation 2:
{3 x + y = 4 | (equation 1)
0 x+(5 y)/3 = 20/3 | (equation 2)
Multiply equation 2 by 3/5:
{3 x + y = 4 | (equation 1)
0 x+y = 4 | (equation 2)
Subtract equation 2 from equation 1:
{3 x+0 y = 0 | (equation 1)
0 x+y = 4 | (equation 2)
Divide equation 1 by 3:
{x+0 y = 0 | (equation 1)
0 x+y = 4 | (equation 2)
Collect results:
Answer: {x = 0
, y = 4
The transaction that is being used is a reflection