All categories

2 years ago

11/12− 1/6q+5/6q−1/3

Mathematics

1 answer:

Contact [7]2 years ago

4 0

Answer: 16/12 = 1 4/12 or 1 2/6

Step-by-step explanation:

convert all the denominators in 12 (common denom.)

11/12 - 2/12 + 10/12 - 4/12

9/12 + 10/12= 19/12 -4/12= 16/12

You might be interested in

You put the names of all the students in your class in a paper bag. There are 19 boys and 12 girls. If you draw a name at random

Rom4ik [11]

Answer:

19 to 12 is the answer

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

un unitățile de măsurat lungimea mai mici decât unitatea principală sunt.......................... ................. Și.........

Alchen [17]

Answer:

english plz !!!!!!!!!!

Step-by-step explanation:

3 0

2 years ago

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constan

vitfil [10]

Answer:

$a = 6m/s^2$

Step-by-step explanation:

Given

When mass = 4kg; Acceleration = 15m/s²

Required

Determine the acceleration when mass = 10kg, provided force is constant;

Represent mass with m and acceleration with a

The question says there's an inverse variation between acceleration and mass; This is represented as thus;

$a\ \alpha\ \frac{1}{m}$

Convert variation to equality

$a = \frac{F}{m}$ ; Where F is the constant of variation (Force)

Make F the subject of formula;

$F = ma$

When mass = 4kg; Acceleration = 15m/s²

$F = 4 * 15$

$F = 60N$

When mass = 10kg; Substitute 60 for Force

$F = ma$

$60 = 10 * a$

$60 = 10a$

Divide both sides by 10

$\frac{60}{10} = \frac{10a}{10}$

$a = 6m/s^2$

<em>Hence, the acceleration is </em> $a = 6m/s^2$ <em />

4 0

2 years ago

I need a answer asap

Murrr4er [49]

Answer:

As the weight increases, the price increases.

6 0

2 years ago

Read 2 more answers

In a recent test, you scored 1.0 standard deviations above the average score attained, and the scores are normally distributed.

sesenic [268]

Answer:

97.75 %

Step-by-step explanation:

You score 1 standard deviation above the mean

a) we have from left tail up to the mean 50 % of all values

b) We have in the interval [ μ - σ ; μ + σ ] 95.5 % of all possible values, if we divide that 95.5 by 2 we get 47.75 %, the part of the values that correspond to the right, then in order to get the % of students scored lower we add

50 + 47.75 = 97.75 %

So you can say that the porcentage of students that scored lower than you is 97.75 %

3 0

2 years ago