artic foxes have thick white fur to keep them warm and also for camouflage in the snow they have small ears to keep the snow out of their ears so that they can hear better they also have thick fur lining and a thick pad on their feet this stops the paws from getting cold and they have short legs so then the body weight can be spread making it easier for the animal to not sink in the snow in the summer the artic fox turns brown to help make the fox invisible when people are hunting in the long grass
Answer:
= 3521m/s
The tangential speed is approximately 3500 m/s.
Explanation:
F = m * v² ÷ r
Fg = (G * M * m) ÷ r²
(m v²) / r = (G * M * m) / r²
v² = (G * M) / r
v = √( G * M ÷ r)
G * M = 6.67 * 10⁻¹¹ * 5.97 * 10²⁴ = 3.98199 * 10¹⁴
r = 32000km = 32 * 10⁶ meters
G * M / r = 3.98199 * 10¹⁴ ÷ 32 * 10⁶
v = √1.24 * 10⁷
v = 3521.36m/s
The tangential speed is approximately 3500 m/s.
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The cyclist's final velocity is 10 m/s.
From the question,
We are to determine the cyclist's final velocity.
<h3>Linear motion</h3>
From one of the equations of motion for linear motion, we have
Where
v is the final velocity
u is the initial velocity
a is the acceleration
and t is the time
From the given information,
The cyclist starts at rest, this means the initial velocity is 0 m/s
That is,
u = 0 m/s
Also
a = 0.5 m/s²
and t = 20 s
Putting the parameters into the equation, we get
Hence, the cyclist's final velocity is 10 m/s.
Learn more on linear motion here: brainly.com/question/19365526
Answer:
Tiempo, t = 6.11 segundos.
Explanation:
Dados los siguientes datos;
Distancia = 140 m
Aceleración = 7,5 m/s²
Dado que el objeto partió del reposo, su velocidad inicial es igual a 0 m/s.
Para encontrar el tiempo, usaríamos la segunda ecuación de movimiento;
S = ut + ½at²
Dónde;
S representa el desplazamiento o la altura medida en metros.
u representa la velocidad inicial medida en metros por segundo.
t representa el tiempo medido en segundos.
a representa la aceleración medida en metros por segundo cuadrado.
Sustituyendo en la ecuación, tenemos;
140 = 0*t + ½*7.5*t²
140 = 0 + 3.75t²
140 = 3.75t²
Dividiendo ambos lados por 3,75, tenemos;
t² = 140/3.75
t = √37.33
Tiempo, t = 6.11 segundos