Solve each of the equations independently, then determine if the are continuous or discontinuous. 15≥-3x [start here] -5≤x [divide both sides by (-3). *Dividing by a negative number means the direction of the sign changes!] x≥-5 [just turned around for analysis]
Next equation: 2/3x≥-2 [start here] x≥-2(3/2) [multiply both sides of the equation by the reciprocal, 3/2) x≥-3
So, (according to the first equation) all values of x must be greater than, or equal to -5.
(According to the second equation) all values of x must be greater than, or equal to -3. So, when graphed on a number line, both equations graph in the same direction, so they are continuous.
Its best to turn fractions into decimals so its easier to solve the problem, in order to do this you would divide the number on the top to the number on the bottom. Ex: 1 divide by 2 So the numerator divided by the denominator. The top of the faction is the numerator and the bottom of the faction is the denominator. So 1 divided by 2 = 0.5 you would replace 0.5 for the 1/2.
