If it's already a negative number it's going to stay as a negative number
Answer: 1/5, 1/2, 0.
Step-by-step explanation:
given data:
no of cameras = 6
no of cameras defective = 3
no of cameras selected = 2
Let p(t):=P(X=t)
p(2)=m/n,
m=binomial(3,2)=3!/2!= 3
n=binomial(6,2)=6!/2!/4! = 15
p(3)= 3/15
= 1/5.
p(1)=m/n,
m=binomial(6,1)*binomial(2,2)=6!/1!/4!*2!/2!/0!= 7.5
n=binomial(6,2)= 15
p(2)= 7.5/15
= 1/2
p(0)=m/n,
m=0
p(0)=0
one angle is 3x-3
another angle is 6(x-10)
Both angles are vertically opposite angles
Vertically opposite angles are always equal
So we equation both the angles and solve for x
3x - 3= 6(x-10)
3x - 3 = 6x - 60
Subtract 6x from both sides
-3x - 3 = -60
Add 3 on both sides
-3x = -57
Divide by 3
x = 19
The value of x= 19
