There are no options provided, therefor I cannot answer the question.
Mass of iron chloride (FeCl₂) : 22.68 g
<h3>Further explanation</h3>
Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements
In the same compound, although from different sources and formed by different processes, it will still have the same composition/comparison
With this law, we can calculate how many grams an element is needed to make a compound with a certain mass, as desired
<h3 />
The iron ions in 50 g mixture :
Answer: Rutherford.
Explanation:
It was the scientist Ernest Rutherford who, by 1911, performed the gold foil experiment in which α particles were shoot to a thin foild of gold.
That experiment showed that although most α particles passed through the thin gold foild, some of them were deviated in small angles and some other were bounced backward.
The conclusion of the experiment was that the atom contained a small dense positively charged nucleous and negative particles (electrons) surroundiing the nucleous. Being the space in between the nucleous and the electrons empty.
Before Rutherford's experiment the model of the atom was that of the plum pudding presented by J.J Thomson, in which the atom was a solid positively charged sphere with embeded negative charge uniformly distributed in it.
Lead reacts very slowly with dilute hydrochloric acid to give lead chloride<span> and </span>hydrogen<span> gas. </span>
<span>lead + hydrochloric acid —> lead chloride + hydrogen
Pb(s) + 2HCl(aq) —> PbCl2(aq) + H2(g)</span>
<span>Lead reacts very slowly with dilute sulphuric acid to give </span>lead sulphate<span> and </span>hydrogen<span> gas. </span>
<span>lead + sulphuric acid —> lead sulphate + hydrogen
Pb(s) + H2SO4 (aq) —> PbSO4(aq) + H2(g)</span>
<span>Lead reacts very slowly with dilute nitric acid to give </span>lead nitrate<span> and </span>hydrogen<span> gas. </span>
<span>lead + nitric acid —> lead nitrate + hydrogen
Fe(s) + 2HNO3(aq) —> Fe(NO3)2(aq) + H2(g)</span><span> </span>
