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2 years ago

Write the full ground-state electron configuration for each: (a) Rb (b) Ge (c) Ar

Chemistry

1 answer:

Natasha_Volkova [10]2 years ago

3 0

Answer:

(a) Rb

$1s^22s^22p^63s^23p^63d^{10}4s^24p^65s^1$

(b) Ge

$1s^22s^22p^63s^23p^63d^{10}4s^24p^2$

$1s^22s^22p^63s^23p^6$

Explanation:

(a) Rb

Atomic number = 37

The electronic configuration is -

$1s^22s^22p^63s^23p^63d^{10}4s^24p^65s^1$

(b) Ge

Atomic number = 32

The electronic configuration is -

$1s^22s^22p^63s^23p^63d^{10}4s^24p^2$

Atomic number- 18

The electronic configuration is -

$1s^22s^22p^63s^23p^6$

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From the given chart;

The wavelength of the atomic emission corresponding to the orange line is 610 nm = 610 x 10⁻⁹ m

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The energy of the emitted photon corresponding to the orange line is calculated as follows;

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