If the arc measures 250 degrees then the range of the central angle lies from π to 1.39π.
Given that the arc of a circle measures 250 degrees.
We are required to find the range of the central angle.
Range of a variable exhibits the lower value and highest value in which the value of particular variable exists. It can be find of a function.
We have 250 degrees which belongs to the third quadrant.
If 2π=360
x=250
x=250*2π/360
=1.39 π radians
Then the radian measure of the central angle is 1.39π radians.
Hence if the arc measures 250 degrees then the range of the central angle lies from π to 1.39π.
Learn more about range at brainly.com/question/26098895
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Let α represent the acute angle between the horizontal and the straight line from the plane to the station. If the 4-mile measure is the straight-line distance from the plane to the station, then
sin(α) = 3/4
and
cos(α) = √(1 - (3/4)²) = (√7)/4
The distance from the station to the plane is increasing at a rate that is the plane's speed multiplied by the cosine of the angle α. Hence the plane–station distance is increasing at the rate of
(440 mph)×(√7)/4 ≈ 291 mph
A/B - 90° | C - 42° | D - 48 | E - 132
Answer:
3:1
You can easily figure out that 60 is a factor of 180 bc 6 is a factor of 18.
So you can simplify it to 18:6
Then divide both sides by 6 and you will get 3:1
Hope this helps ;)
This is 2.5 standard deviations from the mean.
We find this by subtracting the mean from our value, and dividing by the standard deviation:
(63-38)/10 = 25/10 = 2.5