Add 10 to both sides so that the equation becomes 5x^2 + 11x - 2 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -11 ± √(11^2 - 4(5)(-2)) ] / ( 2(5) )
x = [ -11 ± √(121 - (-40) ) ] / ( 10 )
x = [ -11 ± √(161) ] / ( 10)
x = [ -11 ± sqrt(161) ] / ( 10 )
x = -11/10 ± sqrt(161)/10
The answers are -11/10 + sqrt(161)/10 and -11/10 - sqrt(161)/10.
-25/36 is the correct answer to your question
6x + y = -2
y = -3x + 1
Substitute the value of y in first equation,
6x -3x + 1 = -2
3x = -2-1
x = -3/3
x = -1
Now, Substitute it in 2nd equation,
y = -3(-1) + 1
y = 3+ 1 = 4
Coordinates would be: (-1,4) Mark that point and join with origin.
Hope this helps!
Answer:
Step-by-step explanation:
let ∠GEF=x
then ∠GFE=90-x