Answer: 35
Step-by-step explanation:
When two fair dice are thrown , then the sample space would be :
(1,1), (1,2) , (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2) , (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2) , (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2) , (4,3), (4,4), (45), (4,6)
(5,1), (5,2) , (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2) , (6,3), (6,4), (6,5), (6,6)
The total outcomes = 36
We can see that the only outcome in the sample space has sum less than 3 =(1,1)
Now, the number of outcomes in the sample space having sum at-least 3 = 36-1=35
Hence, the number of ways to obtain a sum of at least 3 = 35