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2 years ago

How many moles of AgNO3 are present in 1.50 L of a 0.050 M solution?

2 answers:

8 0

To calculate the moles of AgNO3 in a solution, we need to know the volume and concentration of the solution.
Moles of AgNO3 = Volume of AgNO3 solution (L) * concentration of AgNO3 solution (M or mole/L) = 1.50 L * 0.050 M = 0.075 mole.

So 0.075 moles of AgNO3 are present in 1.50 L of a 0.050 M solution.

Lisa [10]2 years ago

4 0

Answer: 0.075 Moles of AgNO3.

Explanation:

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Answer:

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Explanation:

Hello!

In this case, according to the following chemical reaction:

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Thus, the yielded moles of water are computed by firstly identifying the limiting reactant:

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$p_{H_2O}=\frac{0.0609molH_2O*0.08206\frac{atm*L}{mol*K}*400K}{1.00L}\\\\ p_{H_2O}=2.00atm$

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