You must drive more than 40 miles to make option A the cheaper plan
<em><u>Solution:</u></em>
Two payment options to rent a car
Let "x" be the number of miles driven in one day
<em><u>You can pay $20 a day plus 25¢ a mile (Option A)</u></em>
25 cents is equal to 0.25 dollars
OPTION A : 20 + 0.25x
<em><u>You pay $10 a day plus 50¢ a mile (Option B)</u></em>
50 cents equal to 0.50 dollars
Option B: 10 + 0.50x
<em><u>For what amount of daily miles will option A be the cheaper plan ?</u></em>
For option A to be cheaper, Option A must be less than option B
Option A < Option B
Solve the inequality
Add -0.50x on both sides
Add - 20 on both sides,
Divide both sides by 0.25
Thus you must drive more than 40 miles to make option A the cheaper plan
The graph is misleading because the year’s interval is not constant.
The first year to the second year, the gap is 1 year; in the second to the
third year, the gap is 2; in the third to the fourth year is 4; and the fourth
to the fifth year is 6.
Answer:
4 and 9
Step-by-step explanation:
let their ages be x and x - 5, then in 4 years their ages will be
x + 4 and x - 5 + 4 = x - 1 , and the product is 104, thus
(x + 4)(x - 1) = 104 ← expand factors on left using FOIL
x² + 3x - 4 = 104 ( subtract 104 from both sides )
x² + 3x - 108 = 0 ← in standard form
(x + 12)(x - 9) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 12 = 0 ⇒ x = - 12
x - 9 = 0 ⇒ x = 9
However, x > 0 ⇒ x = 9
Thus
Their present ages are 9 and 9 - 5 = 4
Use photomath. Do not click on the link the other person which is actually a bot put.
