5% of j is 320 what is j

Nesterboy [21]

First, we distribute the 2 through the parenthesis.

3x+2x+8=5(x+1)+3

Then we distribute the 5 through the parenthesis

3x+2x+8=5x+5+3

Collect the like terms

5x+8=5x+5+3

Add the numbers

5x+8=5x+8

The statement is true for any value of x, because both sides are identical

6 0

2 years ago

Which is the graph of f(x) = Square root of x?

natka813 [3]

Answer:

Third option given

Step-by-step explanation:

On a coordinate plane, a parabola opens to the right with a vertex at (0, 0).

use the following x values to plot the associated y values on the x-y plane:

If x = 0, then $y=\sqrt{0} =0$

If x = 1, then $y=\sqrt{1} =1$

If x = 4, then $y=\sqrt{4} =2$

If x = 9, then $y=\sqrt{9} =3$

Join the points and you will find a branch of a parabola opening to the right.

7 0

2 years ago

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Jackie scored 81 and 87 on her first two quizzes . Write and solve a compound inequality to find the possible values for a third

asambeis [7]

Answer:

The third score must be larger than or equal to 72, and smaller than or equal 87

Step-by-step explanation:

Let's name "x" the third quiz score for which we need to find the values to get the desired average.

Recalling that average grade for three quizzes is the addition of the values on each, divided by the number of quizzes (3), we have the following expression for the average:

$average=\frac{81+87+x}{3}$

SInce we want this average to be in between 80 and 85, we write the following double inequality using the symbols that include equal sign since we are requested the average to be between 80 and 85 inclusive:

$80\leq average\leq 85\\80\leq \frac{81+87+x}{3} \leq 85\\80\leq \frac{168+x}{3} \leq 85$

Now we can proceed to solve for the unknown "x" treating each inaquality at a time:

$80\leq \frac{168+x}{3}\\3*80\leq 168+x\\240\leq 168+x\\240-168\leq x\\72\leq x$

This inequality tells us that the score in the third quiz must be larger than or equal to 72.

Now we study the second inequality to find the other restriction on "x":

$\frac{168+x}{3} \leq 85\\168+x\leq 85 *3\\168+x\leq 255\\x\leq 255-168\\x\leq 87$

This ine $72\leq x} \leq 87$ quality tells us that the score in the third test must be smaller than or equal to 87 to reach the goal.

Therefore to obtained the requested condition for the average, the third score must be larger than or equal to 72, and smaller than or equal 87:

4 0

2 years ago

In a triangle, two sides that measure 8 centimeters and 11 centimeters form an angle that measures 82°. to the nearest tenth of

Gwar [14]

We can use the Сosine formula to solve this problem.
First we must find the third side (АС) of the triangle:

$AC^2=AB^2+BC^2-2*AB*BC*cos82^o \\ AC^2=8^2+11^2-2*8*11*0.1392 \\ AC^2=64+121-24.4992= 160.508 \\ AC= \sqrt{160.508} \approx 12.67 \ cm$

The smallest angle of the triangle lies opposite the smallest side, so we need to find m∠C.

$cosC= \frac{AC^2+BC^2-AB^2}{2*AC*BC} \\ \\ cosC= \frac{12.67^2+11^2-8^2}{2*12.67*11}= \frac{160.53+121-64}{278.74} = \frac{217.53}{278.74} \approx 0.7804$

Now we can use Bradis's Table (I don't know the name in English, maybe Trigonometric Table?) to find m∠C:

m∠С = 38°42' = 38.7°

Answer: 38.7°

I hope this helps

7 0

2 years ago

How many centimeters are in 1 mile

kvasek [131]

Answer:

1 mile = 160934 cm

Step-by-step explanation:

1 mile = 1609.34 m

1 m = 100 cm

1 mile = 1609.34 * 100 = 160934 cm

3 0

2 years ago

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