Usually when climbing, it's best to be in the small front ring and the largest back ring. If your cadence is about 100 rpm, then whatever gear you're in is fine. It depends on the road, but as long as your pedaling is at a level you're comfortable with, you're fine.

Explanation:

Google answer by the way.

3 0

2 years ago

A bullet with mass m = 5.21 g is moving horizontally with a speed v = 443 m/s when it strikes a block of hardened steel with mas

AlladinOne [14]

Answer:

0.312 m/s

Explanation:

Elastic collisions conserve momentum and kinetic energy

The velocity of the center of mass will not change. It continues at

0.00521(443) / 14.80521 = 0.155893... ≈ 0.156 m/s

To conserve kinetic energy we can think of the center of mass (CoM) as an ideal spring returning to each mass that strikes it an identical speed of collision in the opposite direction.

The CoM sees the target approach at - 0.156 and will see it depart at 0.156 m/s

A ground based observer sees the target depart at the velocity of the CoM plus the relative velocity .

v = 0.156 + 0.156 = 0.312 m/s

6 0

2 years ago

Calculate a. The heat that must be supplied to a 500.0 g copper kettle containing 400.0 g of water to raise its temperature from

uysha [10]

Explanation:

<h2>For Copper</h2>

dH copper = mCdT copper

<em>(Specific Heat of copper=0.385 J/g C ) </em>

dH = 500 g (0.385 J/g C) (78 C rise)

dH = 15,015 Joules

<h2> For Water</h2>

dH water = m C dT water

<em>(Specific Heat of copper=</em>4.184 J/g-C<em>) </em>

<em />

dH = 400 g (4.184 J/g-C) (78 C rise)

dH = 130,540 Joules

total heat = 15,015 + 130,540 = 145,555 Joules

<h2>Percentage for Water </h2>

(130,540 Joules / 145,555 Joules) x 100 = 89.7 %

If we consider that we have 3 Significant Figures,

then, the answers become ,

15.0 KJ must be added for Copper

130.5 KJ must be added for Water

and the total of 145 KJ must be added in the kettle with the water

89.7 % of heat goes to the Water

7 0

2 years ago