Answer:
a) {15}
b) { }
c) D or {5, 7, 8, 12, 13, 15}
d) no
e) yes
Step-by-step explanation:
a) AUB: even or prime
D - (AUB) = {15}
b) AUC: even or odd; basically all integers
D - (AUC) = { }
c) A∩B : even and prime, that's only 2
D - (A∩B) = {5, 7, 8, 12, 13, 15} = D
d) A and B, both contain 2
Not disjoint
e) A and C are disjoint because no number can be both, even and odd
Answer:
1000 times
Step-by-step explanation:
Given:
The Sun is roughly 10^2 times as wide as the Earth.
The Star KW Sagittarii is roughly 10^5 times as wide as the Earth.
Question asked:
About how many times as wide as the Sun is KW Sagittarii?
Solution:
Let the width of the earth =
As the Sun is roughly 10^2 times as wide as the Earth, hence the width of the sun =
And as the Star KW Sagittarii is roughly 10^5 times as wide as the Earth, hence the width of the Star =
Now, to find that how many times width of the Star KW Sagittarii is as respect to the width of the Sun, we will simply divide:
Width of the Star KW Sagittarii =
Width of the Sun =
x canceled by x
Therefore, Star KW Sagittarii is 1000 times wider than Sun.
<em>First of all we calculated width of Sun in terms of width of earth and then calculated the width of the Star in terms of earth and for comparison we did simple division that showed that the Star KW Sagittarii is 1000 times wider than the Sun.</em>
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1. 2n + 2*5 =2
2. 2n + 10 = 2
3. 2n = 2 -10
4. 2n= -8
5. n = -8/2
6. n = -4
Answer:
The approximate area is A) 5.09cm²
Step-by-step explanation:
Area of a Circle = πr²
r = 1.8
Plug in our values
π(1.8cm²)
Evaluate the area of the entire circle
a = π(1.8cm²)
a = π(3.24cm)
a = 10.179cm²
Area of a sector, with the area of the circle of the sector being a = theta/360 * a
Evaluate the area of the sector
180/360*10.719cm²
0.5 * 10.179cm²
5.0895cm²
Round the value up
5.09cm²
Answer:
26
Step-by-step explanation: You basically add 11 them you are at 0 then add 15 to that number and you get 11+15=26 thats ur answer