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2 years ago

If f(x) x^2-3x find f(-1.8

Mathematics

1 answer:

ICE Princess25 [194]2 years ago

8 0

The answer = 2.16
Good luck

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A class survey in a large class for first-year college students asked, “About how many minutes do you study on a typical weeknig

Anika [276]

Answer: (110.22, 125.78)

Step-by-step explanation:

The confidence interval for the population mean is given by :-

$\mu\ \pm z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given : Sample size = 463

$\mu=118\text{ minutes}$

$\sigma=65\text{ minutes}$

Significance level : $\alpha=1-0.99=0.01$

Critical value : $z_{\alpha/2}=z_{0.005}=\pm2.576$

We assume that the population is normally distributed.

Now, the 90% confidence interval for the population mean will be :-

$118\ \pm\ 2.576\times\dfrac{65}{\sqrt{463}} \\\\\approx118\pm7.78=(118-7.78\ ,\ 118+7.78)=(110.22,\ 125.78)$

Hence, 99% confidence interval for the mean study time of all first-year students = (110.22, 125.78)

3 0

2 years ago

Can someone help me with this?! thanks!!

Vera_Pavlovna [14]

Answer:

you literally just translate each shape by the number of squares specified.

Step-by-step explanation:

for example, move shape 1 5 squares to the right, then 4 down. it will be in the middle area of quadrant 1 (where it already is).

4 0

2 years ago

Read 2 more answers

Which of the following is not a theorem taught from this lesson?

MariettaO [177]

Answer:

The altitude to the base of an isosceles triangle bisects the vertex angle of the triangle.

Step-by-step explanation:

7 0

1 year ago

PLEASE HELP ASAPP!!!!!!!!!!!!!!!

max2010maxim [7]

$\dfrac{1}{3^{-2}x^{-4}y^2}=\dfrac{3^2x^4}{y^2}\\\\\\
\dfrac{3^2\cdot3^4}{(-1)^2}=\dfrac{3^6}{1}=3^6=\boxed{729}$

Answer B)

3 0

2 years ago

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In an international film festival, a penal of 11 judges is formed to judge the best film. At last two films FA and FB were consi

valentina_108 [34]

Answer:

The answer is "0.4329 ".

Step-by-step explanation:

P( three in favor of FA)

Select 3 out of 6 FA supporters then select 2 out of 5 FB supportive judges

$=\frac{^{6}_{C_{3}}\times ^{5}_{C_{2}}}{^{11}_{C_{5}}}\\\\=\frac{\frac{6!}{3!(6-3)!}\times \frac{5!}{2!(5-2)!}}{\frac{11!}{5!(11-5)!}}\\\\=\frac{\frac{6!}{3! \times 3!}\times \frac{5!}{2! \times 3!}}{\frac{11!}{5! \times 6!}}\\\\=\frac{\frac{6 \times 5 \times 4 \times 3!}{3 \times 2 \times 1\times 3!}\times \frac{5 \times 4 \times 3!}{2 \times 1 \times 3!}}{\frac{11 \times10 \times 9 \times 8 \times 7 \times 6! }{5 \times 4 \times 3 \times 2 \times 1 \times 6!}}\\\\$

$=\frac{ (5 \times 4) \times(5 \times 2)}{(11 \times 3 \times 2 \times 7 )}\\\\=\frac{ 20 \times 10 }{(11 \times 42)}\\\\=\frac{ 200 }{462}\\\\=\frac{100 }{231}\\\\=0.4329$

6 0

2 years ago